----- The following copyright 1991 by Dirk Terrell ----- This article may be reproduced or retransmitted ----- only if the entire document remains intact ----- including this header Lecture #9 "Burning the Ashes" Although I detect the usual eagerness to jump to the 'flashy' (no pun intended, well, maybe a little bit) subjects of supernovae, white dwarfs, black holes, etc., I thought it might be good to go into a little detail about how elements are formed first, since I detect a little misunderstanding about it. To do this, let's look at what happens to a star of 15 solar masses (that is, starts out with 15 times as much mass as the sun) once all of the hydrogen in the core is consumed. At this point the core of the star consists of helium "ash" left over from the fusion of hydrogen. Since there is no longer enough pressure support to balance the gravitational force (i.e. the weight of the overlying layers) the core collapses as we said last time. This collapse releases a lot of energy, enough, in fact, to cause the hydrogen in the layers above the helium core to become hot enough to begin fusing hydrogen in a thin shell around the core. We are very original and call this a hydrogen shell source. As the core collapses, the temperature rises and eventually becomes high enough that helium nuclei can start fusing together to form beryllium (Be). The Be nucleus is unstable and will break back down into two He unless another He nucleus combines with it to form carbon (C). The He nuclei contain two protons and two neutrons. The Be nucleus, therefore, contains four protons and four neutrons. The C atom has six protons and six neutrons. The net result of these reactions is that three helium nuclei combine to form a carbon nucleus (notice that we are forming NUCLEI, not atoms. The temperature and pressure in the core of a star are much to high for the binding of electrons to the nuclei.) This process of helium fusion is known as the triple alpha process because alpha particles that were discovered in the late nineteenth century in radiactive decays turned out to be helium nuclei. Now, these C nuclei can combine with He nuclei to form oxygen, with 8 protons and eight neutrons. There is also a small amount of neon and magnesium produced. When the helium in the core is exhausted, what is left is carbon and oxygen. The core again contracts, this time causing a helium shell source to be created. Now we have a star with a carbon-oxygen core, a helium shell source just above the core, and a hydrogen shell source above that. Carbon fusion will occur when the temperature in the core reaches about 800,000,000 Kelvins (same as centigrade at this point). Soon the carbon is used up, the core contracts, and a carbon shell source is set up. Our star will continue to go through the same cycle with neon fusion, oxygen fusion, and finally silicon fusion. Nope, that isn't a typo. Neon which is atomic weight 20, fuses before oxygen, which is atomic weight 16. How does that happen, you ask? At these high temperatures, a process known as photodisintegration becomes important. Basically what happens is that photons have energies high enough to break apart these nuclei. It turns out that a neon nucleus is held together a little less tightly than an oxygen nucleus. Thus photons can break the neon apart more easily than the oxygen. When the neon is broken apart it splits into an oxygen and a helium nucleus. The helium nucleus can then combine with another neon nucleus to form magnesium. Oxygen burning's products are silicon and sulfur. Photodisintegrations continue and helium and hydrogen nuclei combine with silicon to form heavier elements. When silicon burning is completed, the core of the star contains primarily iron-group nuclei like chromium, cobalt, nickel, manganese, and iron. At first you might expect the iron core to contract, and proceed with iron burning. Well, the core does contract, but iron fusion does not take place. Iron nuclei (atomic weight 56) are the most tightly bound nuclei there are. If the iron nuclei were to combine with, say, helium nuclei, energy would have to be absorbed, rather than released. We say that the reaction is endothermic (takes energy) rather than exothermic (releases energy). The star finds itself in quite a predicament. Up till now it has managed to stave off gravity by 'burning' nuclear fuels. Now, there is no more fuel. What happens now? Tune in next time! Dirk