On the night of October 15, 1991, the Fly's Eye detected a proton with an energy of 3.2±0.9×10^20 electron volts.[1,2] By comparison, the recently-canceled Superconducting Super Collider (SSC) would have accelerated protons to an energy of 20 TeV, or 2×10^13 electron volts--ten million times less. The energy of the Oh My God particle seen by the Fly's Eye is equivalent to 51 joules--enough to light a 40 watt light bulb for more than a second--equivalent, in the words of Utah physicist Pierre Sokolsky, to "a brick falling on your toe." The particle's energy is equivalent to an American baseball travelling fifty-five miles an hour.
All evidence points to these extremely high energy particles being protons--the nuclei of hydrogen atoms. Recalling that the rest mass of the proton is 938.28 MeV--roughly 1 GeV, 1×10^9 eV, all of the rest of the particle's energy results from the kinetic energy resulting from its motion, which we can calculate according to basic formulae of special relativity. So let's crunch a few numbers.
M_0 M = ------------ [1] v² Sqrt[1 - --] c²
where M_0 is the particle's rest mass, 0, v is the particle's velocity, and c is the speed of light. Okay, we know that the Oh My God proton has a rest mass of about 1 GeV, and a total kinetic energy of 3×10^20 eV, so let's solve equation [1] for v, setting c to 1 to obtain velocity as a fraction of the speed of light:
v = Sqrt[m² - M_0²] / m
And thus, approximately:
v = 0.9999999999999999999999951 c
So taking 3×10^8 metres per second as the speed of light, we find that the particle was traveling 2.9999999999999999999999853×10^8 metres per second, thus 1.467×10^-15 metres per second slower than light--one and a half femtometres per second slower than light. If God's radar gun is slightly out of calibration, this puppy's gonna be doin' hard time for speeding. After traveling one light year, the particle would be only 0.15 femtoseconds--46 nanometres--behind a photon that left at the same time.
t0 t = ------------ v² Sqrt[1 - --] c²
Since we know v/c, we can immediately calculate:
t -- = 3.197×10^11 t0
and thus, moving in the reference frame of the particle, time passes three hundred billion times slower than in a rest frame. Thus, given that the particle travels with essentially the speed of light, an observer traveling along with the particle would perceive the flight time from the following objects to the Earth.
Distance[3] Perceived Object (light years) Travel Time =============== ================== =========== Alpha Centauri 4.36 0.43 milliseconds Galactic nucleus 32,000 3.2 seconds Andromeda galaxy 2,180,000 3.5 minutes Virgo cluster 42,000,000 1.15 hours Quasar 3C273 2,500,000,000 3 days Edge of universe 17,000,000,000 19 days
Thus, if you could accelerate yourself to the speed at which the Oh My God particle was traveling, you'd be able to travel to the edge of the visible universe in a couple of weeks. Unfortunately, even assuming you found a source for the energy it would take and invented a means to accelerate yourself and Intergalactic Vessel Omega Point to this velocity, you wouldn't get far before being disrupted into subatomic goo due to interactions with photons in the ubiquitous cosmic microwave background radiation. Sokolsky has calculated that at 3×10^20 eV, even a single proton could travel no farther than 10 megaparsecs, about the distance of the Virgo galaxy cluster, before losing energy in this manner.
l v² -- = Sqrt[1 - --] l0 c²
And thus, paralleling the time dilation calculated above, in the frame of the particle, oncoming objects are seen as contracted by a factor of 3×10^11, three hundred billion times, in thickness. Thus, seen from the particle, the objects below will have the following thickness.
Object Rest Frame Thickness Particle Frame Thickness ================ ==================== ======================== Earth's diameter 12,756 km 0.0399 mm Solar system 80 AU 37 metres Sun/Alpha Centauri 4.3 light years 127 km (79 miles) Milky Way galaxy 30 kiloparsecs 2,895,000 km, about ten times the distance from the Earth to the Moon
Nobody knows. A particle with such energy would be deflected little by galactic magnetic fields, and so its impact track should point right back at the source. Astronomers see nothing unusual in that direction.
Nature remains rich in mysteries.