SUBROUTINE SGBSL(ABD,LDA,N,ML,MU,IPVT,B,JOB)
      INTEGER LDA,N,ML,MU,IPVT(1),JOB
      REAL ABD(LDA,1),B(1)
C
C     SGBSL SOLVES THE REAL BAND SYSTEM
C     A * X = B  OR  TRANS(A) * X = B
C     USING THE FACTORS COMPUTED BY SGBCO OR SGBFA.
C
C     ON ENTRY
C
C        ABD     REAL(LDA, N)
C                THE OUTPUT FROM SGBCO OR SGBFA.
C
C        LDA     INTEGER
C                THE LEADING DIMENSION OF THE ARRAY  ABD .
C
C        N       INTEGER
C                THE ORDER OF THE ORIGINAL MATRIX.
C
C        ML      INTEGER
C                NUMBER OF DIAGONALS BELOW THE MAIN DIAGONAL.
C
C        MU      INTEGER
C                NUMBER OF DIAGONALS ABOVE THE MAIN DIAGONAL.
C
C        IPVT    INTEGER(N)
C                THE PIVOT VECTOR FROM SGBCO OR SGBFA.
C
C        B       REAL(N)
C                THE RIGHT HAND SIDE VECTOR.
C
C        JOB     INTEGER
C                = 0         TO SOLVE  A*X = B ,
C                = NONZERO   TO SOLVE  TRANS(A)*X = B , WHERE
C                            TRANS(A)  IS THE TRANSPOSE.
C
C     ON RETURN
C
C        B       THE SOLUTION VECTOR  X .
C
C     ERROR CONDITION
C
C        A DIVISION BY ZERO WILL OCCUR IF THE INPUT FACTOR CONTAINS A
C        ZERO ON THE DIAGONAL.  TECHNICALLY THIS INDICATES SINGULARITY
C        BUT IT IS OFTEN CAUSED BY IMPROPER ARGUMENTS OR IMPROPER
C        SETTING OF LDA .  IT WILL NOT OCCUR IF THE SUBROUTINES ARE
C        CALLED CORRECTLY AND IF SGBCO HAS SET RCOND .GT. 0.0
C        OR SGBFA HAS SET INFO .EQ. 0 .
C
C     TO COMPUTE  INVERSE(A) * C  WHERE  C  IS A MATRIX
C     WITH  P  COLUMNS
C           CALL SGBCO(ABD,LDA,N,ML,MU,IPVT,RCOND,Z)
C           IF (RCOND IS TOO SMALL) GO TO ...
C           DO 10 J = 1, P
C              CALL SGBSL(ABD,LDA,N,ML,MU,IPVT,C(1,J),0)
C        10 CONTINUE
C
C     LINPACK. THIS VERSION DATED 08/14/78 .
C     CLEVE MOLER, UNIVERSITY OF NEW MEXICO, ARGONNE NATIONAL LAB.
C
C     SUBROUTINES AND FUNCTIONS
C
C     BLAS SAXPY,SDOT
C     FORTRAN MIN0
C
C     INTERNAL VARIABLES
C
      REAL SDOT,T
      INTEGER K,KB,L,LA,LB,LM,M,NM1
C
      M = MU + ML + 1
      NM1 = N - 1
      IF (JOB .NE. 0) GO TO 50
C
C        JOB = 0 , SOLVE  A * X = B
C        FIRST SOLVE L*Y = B
C
         IF (ML .EQ. 0) GO TO 30
         IF (NM1 .LT. 1) GO TO 30
            DO 20 K = 1, NM1
               LM = MIN0(ML,N-K)
               L = IPVT(K)
               T = B(L)
               IF (L .EQ. K) GO TO 10
                  B(L) = B(K)
                  B(K) = T
   10          CONTINUE
               CALL SAXPY(LM,T,ABD(M+1,K),1,B(K+1),1)
   20       CONTINUE
   30    CONTINUE
C
C        NOW SOLVE  U*X = Y
C
         DO 40 KB = 1, N
            K = N + 1 - KB
            B(K) = B(K)/ABD(M,K)
            LM = MIN0(K,M) - 1
            LA = M - LM
            LB = K - LM
            T = -B(K)
            CALL SAXPY(LM,T,ABD(LA,K),1,B(LB),1)
   40    CONTINUE
      GO TO 100
   50 CONTINUE
C
C        JOB = NONZERO, SOLVE  TRANS(A) * X = B
C        FIRST SOLVE  TRANS(U)*Y = B
C
         DO 60 K = 1, N
            LM = MIN0(K,M) - 1
            LA = M - LM
            LB = K - LM
            T = SDOT(LM,ABD(LA,K),1,B(LB),1)
            B(K) = (B(K) - T)/ABD(M,K)
   60    CONTINUE
C
C        NOW SOLVE TRANS(L)*X = Y
C
         IF (ML .EQ. 0) GO TO 90
         IF (NM1 .LT. 1) GO TO 90
            DO 80 KB = 1, NM1
               K = N - KB
               LM = MIN0(ML,N-K)
               B(K) = B(K) + SDOT(LM,ABD(M+1,K),1,B(K+1),1)
               L = IPVT(K)
               IF (L .EQ. K) GO TO 70
                  T = B(L)
                  B(L) = B(K)
                  B(K) = T
   70          CONTINUE
   80       CONTINUE
   90    CONTINUE
  100 CONTINUE
      RETURN
      END