Subject: sci.math FAQ: Surface Area of Sphere
Summary: Part 35 of many, New version,
Date: Fri, 17 Nov 1995 17:16:30 GMT
Nntp-Posting-Host: neumann.uwaterloo.ca


Archive-Name: sci-math-faq/surfaceSphere
Version: 6.2




Formula for the Surface Area of a sphere in Euclidean N -Space



   This is equivalent to the volume of the N -1 solid which comprises the
   boundary of an N -Sphere.

   The volume of a ball is the easiest formula to remember: It's r^N
   (pi^(N/2))/((N/2)!) . The only hard part is taking the factorial of a
   half-integer. The real definition is that x! = Gamma (x + 1) , but if
   you want a formula, it's:

   (1/2 + n)! = sqrt(pi) ((2n + 2)!)/((n + 1)!4^(n + 1)) To get the
   surface area, you just differentiate to get N (pi^(N/2))/((N/2)!)r^(N
   - 1) .

   There is a clever way to obtain this formula using Gaussian integrals.
   First, we note that the integral over the line of e^(-x^2) is sqrt(pi)
   . Therefore the integral over N -space of e^(-x_1^2 - x_2^2 - ... -
   x_N^2) is sqrt(pi)^n . Now we change to spherical coordinates. We get
   the integral from 0 to infinity of Vr^(N - 1)e^(-r^2) , where V is the
   surface volume of a sphere. Integrate by parts repeatedly to get the
   desired formula.

   It is possible to derive the volume of the sphere from ``first
   principles''.


     _________________________________________________________________



    alopez-o@barrow.uwaterloo.ca
    Tue Apr 04 17:26:57 EDT 1995
   
   
   
